Answer: You can say that the electric flux will be zero as result of Gauss’s Law. Enclosing any number of charges who’s sum equals zero will result in a surface flux of zero.

## What is electric flux through the Gaussian surface enclosing an electric dipole?

We have an **electric dipole**. … Now, the total charge **enclosed** by our **Gaussian surface** is zero, so according the **Gauss**‘ Law the **flux through the Gaussian surface** is zero, and so is the **electric field** intensity due the **electric dipole**.

## When an electric dipole is held at an angle?

Answer: the forces experienced by the 2 charges constituting the electric dipole when placed in an uniform external electric field are equal and opposite in nature, the net force on the dipole **is zero**. No torque act on the dipole when the moment of electric dipole is parallel to the electric field.

## What is the net electric flux through a closed surface?

The net electric flux is **zero** through any closed surface surrounding a zero net charge. Therefore, if we know the net flux across a closed surface, then we know the net charge enclosed.

## How does electric field of an electric dipole vary with distance?

A short dipole is placed at the origin with dipole moment directed along positive x-axis. The electric intensity at **a point P on x-axis**, at distance much greater than the dipole length E. If the dipole is rotated clockwise by 90∘, why will be the value and direction of electric intensity at P (x,0).

## What is electric flux through a closed surface?

According to Gauss’s law, the flux of the electric field →E through any closed surface, also called a Gaussian surface, is **equal to the net charge enclosed (qenc) divided by the permittivity of free space (ϵ0):** **ΦClosedSurface=qencϵ0.**

## What is the formula of electric field of a dipole?

The formula for electric dipole moment for a pair of equal & opposite charges is **p = qd**, the magnitude of the charges multiplied by the distance between the two.

## Are deflected in electric field?

X-rays are **electromagnetic** waves and are not charged. Neutrons are charge-less. Alpha particles are basically helium nuclei and are charged. So they **are deflected** in the **electric field**.